8x^2+16x=37

Solution for 8x^2+16x=37 equation:

8x^2+16x=37

We move all terms to the left:

8x^2+16x-(37)=0

a = 8; b = 16; c = -37;
Δ = b2-4ac
Δ = 162-4·8·(-37)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-12\sqrt{10}}{2*8}=\frac{-16-12\sqrt{10}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+12\sqrt{10}}{2*8}=\frac{-16+12\sqrt{10}}{16}
$